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even i enter 3 number this message is always displayed "Enter 3 number please"
here is the code
echo enter 3 numbers
read n1 n2 n3
if test "$n1" -o -z "$n2" -o -z "$n3"
then
echo "Enter 3 number please"
elif [ $n1 -ge $n2 -a $n1 -a $n3 ]
then
echo $n1 is maximum number
elif [ $n2 -ge $n1 -a $n2 -a $n3 ]
then
echo $n2 is maximum number
elif [ $n3 -ge $n1 -a $n3 -a $n2 ]
then
echo $n2 is maximum number
fi
Yep found that out myself too. The logic is not correct. Here's a working version:
Code:
#!/bin/bash
echo "enter 3 numbers"
read n1 n2 n3
if [ -z "$n1" -o -z "$n2" -o -z "$n3" ]
then
echo "Enter 3 numbers please."
elif [ $n1 -ge $n2 ] && [ $n1 -ge $n3 ] # Both must be true
then
echo $n1 is maximum number
elif [ $n2 -ge $n3 ] # now we only need to check if n2 >= n3
then
echo $n2 is maximum number
else # If we get here, n3 must be it.
echo $n3 is maximum number
fi
If parts of the code are unclear, don't hesitate to ask.
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