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tommytomato 02-03-2004 07:04 PM

mysql error on boot up
 
can any one tell me were to add the command please

Quote:

noticed the same startup problems only after I assigned a password to the mysql root user. The problem is in the mysqladmin ping command in the mysql startup script, it apparently doesn't work after assigning the root user a password. So I modified the script and in the mysqladmin ping commands added the "-u root -p 'password' " and the script works fine now. Thats not the best solution but does seem to work.
Os is Fedora Core 1 /etc/init.d


Code:

#!/bin/bash
#
# mysqld        This shell script takes care of starting and stopping
#                the MySQL subsystem (mysqld).
#
# chkconfig: - 78 12
# description:        MySQL database server.
# processname: mysqld
# config: /etc/my.cnf
# pidfile: /var/run/mysqld/mysqld.pid

# Source function library.
. /etc/rc.d/init.d/functions

# Source networking configuration.
. /etc/sysconfig/network


prog="MySQL"

datadir="/var/lib/mysql"

start(){
        touch /var/log/mysqld.log
        chown mysql.mysql /var/log/mysqld.log
        chmod 0640 /var/log/mysqld.log
        if [ ! -d $datadir/mysql ] ; then
            action $"Initializing MySQL database: " /usr/bin/mysql_install_db
            ret=$?
            chown -R mysql.mysql $datadir
            if [ $ret -ne 0 ] ; then
                    return $ret
            fi
        fi
        chown -R mysql.mysql $datadir
        chmod 0755 $datadir
        /usr/bin/safe_mysqld  --defaults-file=/etc/my.cnf >/dev/null 2>&1 &
        ret=$?
        # Spin for a maximum of ten seconds waiting for the server to come up
        if [ $ret -eq 0 ]; then
            for x in 1 2 3 4 5 6 7 8 9 10; do
            if [ -n "`/usr/bin/mysqladmin ping 2> /dev/null`" ]; then
                    break;
            else
                    sleep 1;
            fi
            done
            if !([ -n "`/usr/bin/mysqladmin ping 2> /dev/null`" ]); then
                    echo "Timeout error occurred trying to start MySQL Daemon."
                    action $"Starting $prog: " /bin/false
            else
                    action $"Starting $prog: " /bin/true
            fi
        else
                action $"Starting $prog: " /bin/false
        fi
        [ $ret -eq 0 ] && touch /var/lock/subsys/mysqld
        return $ret
}

stop(){
        /bin/kill `cat /var/run/mysqld/mysqld.pid  2> /dev/null ` > /dev/null 2>&1
        ret=$?
        if [ $ret -eq 0 ]; then
            action $"Stopping $prog: " /bin/true
        else
                action $"Stopping $prog: " /bin/false
        fi
        [ $ret -eq 0 ] && rm -f /var/lock/subsys/mysqld
        [ $ret -eq 0 ] && rm -f $datadir/mysql.sock
        return $ret
}
 
restart(){
    stop
    start
}

condrestart(){
    [ -e /var/lock/subsys/mysqld ] && restart || :
}

# See how we were called.
case "$1" in
  start)
    start
    ;;
  stop)
    stop
    ;;
  status)
    status mysqld
    ;;
  restart)
    restart
    ;;
  condrestart)
    condrestart
    ;;
  *)
    echo $"Usage: $0 {start|stop|status|condrestart|restart}"
    exit 1
esac

exit $?

TT :newbie: :study:

tommytomato 02-03-2004 08:03 PM

Hi just an updated.

I got this from a mate

Quote:

Its not good to put password on the command line cause then it appears in the environment for that program and thusly can be seen/copied for use by hackers.

You can see this for yourself by typing 'ps aufxww' on the cmd line.

any other ideas please.

TT :newbie: :study:


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