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Move file contents to another file with bash script (find, mimetype and cat)

Hi There :)

I get some files from my ftp and now I want to sort them. Some are images, some are text files which contain one link each. I want to sort the files with a while loop. Here is what I have done so far.

Code:

#!/bin/bash



#: Script for getting stuff from the ftp

#: Step 1 will get the files

#: Step 2 will get the links :)

#: Step 3 will follow the links



HOST=192.111.222.333

USER=username

PASS=userpass



# Step 1. Uses the ftp command with the -inv switches.  -i turns off interactive prompting. -n Restrains FTP from attempting the auto-login feature. -v enables verbose and progress. 



ftp -inv $HOST << EOF



user $USER $PASS



cd some/dir



mget *

mdelete *

bye

EOF

 

#: Step 2

#: Check img-folder / create it

if [ ! -d "images" ]; then

  mkdir images

fi



#: link-list there?

if [ ! -f "temp.list" ]; then

  touch "temp.list"

fi



while read -a Files; do

  if [[ $(mimetype -b "${Files}") == "text/plain" ]]; then

    cat "${Files}" | sort >> temp.list

#    rm "$Files"

  fi



  if [[ $(mimetype -b "${Files}") == "image/jpg" ]]; then

    mv "${Files}" "images/${Files}"

  fi

done < <(find * -maxdepth 0 -type f ! -name "*.list" ! -name "*.sh")

cat does not work somehow. I tried many things with IFS and other hints I found on the web but it seems not easy to get the two arguments (find, mimetype) working with cat. I also tried to remove the spaces in all filenames and so on.

The optimal solution would be, if the resulting textfile contains the filename and in the next line the link from the file.

Maybe it's just a small thing I forgot...?

I am not sure I follow the logic??

1. read -a Files -> this means read into the array Files - as find will return each item found, why would you want to read them into an array?

2. you refer to ${Files} throughout the loop -> again see above but this is not how you would refer to an array, should be something like ${Files[@]}

3. cat "${Files}" | sort >> temp.list - you mentioned that the files contain one link each (I look at this as saying only one line in each file) ... if this is the case there is nothing to sort??
So this should just be:

Code:

cat "${Files}" >> temp.list

4. I am not familiar with the 'mimetype' command, but are you 100% that the output is exactly what you have listed? Remembering that any whitespace or different case would make the tests fail

5. personally I would use a for loop with globbing and pass if the files are not the ones your looking for (again though ... that is just my thought on that one)

Hope some of that helps