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Hi. I realise that the answer to this question is probably in the man page, but I seem to be incapable of finding it!
I would like to use the 'ls' command to display directories only. (Equivalent of MSDOS 'dir /ad')
I've tried:
ls -d *
ls --directory *
ls -ldR *
together with various combinations of the above. Nothing I have tried seems to give me what I want, and I am starting to get a little frustrated. Please put me out of my misery!...
Keep in mind that it's really your shell that is expanding that "*/" to a list of directories that is then seen by ls. What is probably happening is that your MP3 directory has a subdirectory with a name beginning with '-', and ls tries to process that entire name as a set of flag arguments. Try this:
Keep in mind that it's really your shell that is expanding that "*/" to a list of directories that is then seen by ls. What is probably happening is that your MP3 directory has a subdirectory with a name beginning with '-', and ls tries to process that entire name as a set of flag arguments. Try this:
Code:
ls -d -- */
Gee that worked just swell! Thanx!
The offending directory is appropriate -----> -=A3-Sopranos Soundtrack=-//
You're absolutely right!
Do I understand you to mean
[norm@linux-2 ~]$ ls -l -a # aaaah! I see how the -=A3Sopranos would get expanded by bash
total 10492
drwx------ 79 norm norm 4096 Jul 17 14:06 ./
ls -d */ shell expands */ to all lines ending in / then passes it all to ls -d -=A3Sopranos
BUT -=A3Sopranos is not the first entry so ls must be checking to see if it can list EVERYTHING without errors before ANYTHING is sent to stdout ie display. Is that right?
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