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Old 12-17-2010, 06:45 PM   #1
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Registered: Apr 2009
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Distribution: Fedora (2011), DreamLinux(2010), SUSE(2009))
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Location of a program running in terminal, launched from panel.

Hi all,
I am using DreamLinux.
I have pinned a program, that runs in terminal, to the launcher in the panel on desktop.
The program's executable file (name: feap) is located in

After I added the launcher to the panel that runs the file in terminal, the program asks for the input file (text file with alot of commands) when run.
By default the program accepts the files that are located in the same directory i.e. /feap2.2 , so I placed the input file in the same directory.
However when I run the program from the panel, and give the input file name, it says no such file exists. Then I gave the file name with full path, but problem was not solved. I have tried alot e.g. placed the input file at other locations, but all in vain. I have set all input file permissions to be accessible by User as well.
I will be much relieved if someone suggests where to place the input file for the such program running in the terminal launched from panels?

P.S: If I open terminal, go to the directory (/home/User/feap2.2), run the program's exe file, and then give the file name, it accepts the input file and it give results.
Old 12-17-2010, 09:24 PM   #2
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There is probably some cleaner way to do what you're trying wit just your GUI, but since I'm not familiar with that, I will suggest wrapping the whole business in a shell script that changes to the proper directory, sets any necessary environment variables, etc. and then launches your program with appropriate arguments. Should be easy to write, easy to test, etc.

--- rod.

EDIT: Upon re-reading your post, I wish to get clarification. Does the program require you to interactively enter some filename? If so, and unless there is a commandline option to specify the file name, then your script will probably require the expect tool.

Last edited by theNbomr; 12-17-2010 at 09:26 PM.


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