list file
 

I use Redhat server , I know each user local directory have a .forward file which re-direct the mail , can advise if I would like to list all the .forward file content and the corresponding user id , just like as below , what can i do ? Thanks.

user id .forward
======== ========
user1 user1@domain.com
user2 user2@domain.com
user3 user3@domain.com
" "
" "

If I understand well the main problem is to retrieve the list of users and their home directories, right? The most straightforward method is to parse the /etc/passwd file using awk. For example, suppose the real (not system) users have ID greater than (or equal to) 500:
You can use the printf statement in place of print to customize/columnize the output. If you want to write down the header, add a print(f) statement in the BEGIN section of awk. Hope this helps.

thx reply,

I tried your method , but no output .

what I would like is just to list all user's .forward content .

thx

Can I just query
Although its possible, by default these are not setup on most systems.
In fact its been a long time since I've seen one 'in the wild'
It is normal to have /etc/aliases setup, which is more like a system wide .forward.

thx reply ,

No need to worry if the .forward or not , I just would like to know the content of .forward file .

Thx

Hi,

quick and dirty. Assumes user home dirs are in /home:
Or if you want to also print out the file name
A better approach could involve using some thing like "getent passwd"
to determine the users home directory (similar to coulix's method).

HTH,

Evo2.