increment in hex

snutz411 · 11-01-2005, 04:33 PM

is there a way i can write a shell script that will be able to increment in hex?

i.e. i was to get all the values from 000 to FFF

Dark_Helmet · 11-01-2005, 04:47 PM

Incrementing by one in hex is the same as incrementing by one in any other number base

My suggestion: Do the increment like normal, and manually convert to hex format when you need to display or compare it to a hex value.

For instance:

Code:

#!/bin/bash

for number in $( seq 1 255 )
do
  hex_representation=$( printf "%X" ${number} )
  echo "${number}: ${hex_representation}"
done

If you're script is given the value of the number to increment in hex notation, you can also use printf to convert it to decimal for you:

Code:

number=$( printf "%d" 0x${hex_representation}" )

I'm not claiming that any of this is efficient by any means. Nor am I saying it will solve all your problems

But it should give you a start.

solveit · 11-01-2005, 05:54 PM

Try this :

Code:

i=0

while [ $i  -lt  4096 ]
do
   x=`printf "%04X\n"  $i`
   echo $x
   i=`expr $i + 1`
done