I need a command that shows installation directories.
 

I am new to Linux and I am currently using Red Hat 9.0 professional. I am trying to remove the version of Apache that comes in the distribution but I am unsure as to how I should proceed. I would very much like to know if there is a command or some kind of tool that will list the various files associated with a program and where they are located? The RPM command has a feature that does this, but is there one for apps built from source? Any information would be most appreciated. Thanks

The Makefile would be the safest bet, I guess ...


Cheers,
Tink

most often you can cd into the source code folder and give the command "make uninstall"

If ever you install it by package RPM can I still use the "make clean" or "make uninstall" command..???:confused: :confused: :confused:

If it's a binary rpm you use rpm -e to remove it...

Well, I did this...

Just use the actual package name. It will be something like:

rpm -e rh9.ymessenger

I actually did that and same things happen...

[root@ryan Installers]# rpm -e rh9.ymessenger-1.0.4-1.i386.rpm
error: package rh9.ymessenger-1.0.4-1.i386.rpm is not installed
[root@ryan Installers]#

Ah, did you actually try it without the version number?

If you can't figure the name then maybe you can use a gui rpm tool to find th package...

I'm using mandrake... how can use the GUI RPM???

Mandrake control center has a packages setup. Go to the uninstall section and see if you see the package in there...

Got it Thanks amosf