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Old 12-23-2016, 04:06 AM   #1
ROOTS_S
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How to zip csv files having specific pattern in a directory using UNIX shell script?


I have files in a Linux directory . Some of the file is listed below

Quote:
-rw-rw-r--. 1 roots roots 0 Dec 23 02:17 zzz_123_00000_A_1.csv
-rw-rw-r--. 1 roots roots 0 Dec 23 02:18 zzz_121_00000_A_2.csv
-rw-rw-r--. 1 roots roots 0 Dec 23 02:18 zzz_124_00000_A_3.csv
drwxrwxr-x. 2 roots roots 6 Dec 23 02:18 zzz
-rw-rw-r--. 1 roots roots 0 Dec 23 02:54 yyy_123_343434_A_1.csv
-rw-rw-r--. 1 roots roots 0 Dec 23 02:55 yyy_123_343434_A_1.xml
-rw-rw-r--. 1 roots roots 0 Dec 23 02:55 yyy_1254_343434_A_1.csv
-rw-rw-r--. 1 roots roots 0 Dec 23 02:55 yyy_1254_343434_A_1.txt
drwxrwxr-x. 2 roots roots 6 Dec 23 02:56 yyy
In my directory other file formats also there with same name. And my direcotry might have sub directory also. I should not consider other files and sub directories for zip process.
Once zip is done,I have to move this csv files into archive directory. I have to write unix script.

Expected Output:

Quote:
zzz_timestamp.zip
should have
Quote:
zzz_123_00000_A_1.csv,zzz_121_00000_A_2.csv and zzz_124_00000_A_3.csv
Quote:
yyy_timestamp.zip
should have
Quote:
yyy_123_343434_A_1.csv,yyy_1254_343434_A_1.csv
Please let me know how to implement this task.
 
Old 12-23-2016, 04:27 AM   #2
syg00
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Quote:
Originally Posted by ROOTS_S View Post
I have to write unix script.
Indeed you do. Not us.
What have you tried ?.
 
Old 12-23-2016, 04:29 AM   #3
Turbocapitalist
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Work out each step manually first.

I would start with find and work out a formula that will show you the list of files to be archived. Then pass that to tar or "zip"

Once you have that, copy the line and modify the copy so that it moves the files to the directory of your choice.
 
Old 12-23-2016, 06:36 AM   #4
Habitual
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Show us your work.
 
  


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