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01-19-2010, 04:00 AM
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#1
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Member
Registered: Dec 2009
Posts: 41
Rep:
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How to use find with two lines together?
I am trying to search for
Code:
<cats>
Sports
</cats>
how do i use the find command to search for <cats>Sports
The problem here is that the word Sports is in the next line of <cats> so I cant use -
Code:
find /test/upload/ -type f -name "*.xml" -exec grep -l "<cats>Sports" {} \; -print
How do I put the next line string? plz help..
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01-19-2010, 05:21 AM
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#2
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LQ Addict
Registered: Jul 2002
Location: East Centra Illinois, USA
Distribution: Debian stable
Posts: 5,908
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Try this:
Code:
find /test/upload/ -type f -name "*.xml" -exec grep -l -A 1 -B 1 "Sports" {} \; -print
-A 1 print one line After the line containing Sports
-B 1 print one line Before the line containing Sports
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01-19-2010, 05:49 AM
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#3
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Member
Registered: Dec 2009
Posts: 41
Original Poster
Rep:
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thx but the file might contains a reference of word Sports anywhere so that command showed me all the files which ever contained the word sports irrespective of where the word is present.
the only unique reference is when sports is within <cats>
I just wanted to see the files which contains word withing <cats>
Quote:
Originally Posted by bigrigdriver
Try this:
Code:
find /test/upload/ -type f -name "*.xml" -exec grep -l -A 1 -B 1 "Sports" {} \; -print
-A 1 print one line After the line containing Sports
-B 1 print one line Before the line containing Sports
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01-19-2010, 05:58 AM
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#4
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LQ Guru
Registered: Jan 2009
Location: Japan
Distribution: Mostly Debian and CentOS
Posts: 6,726
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Grep is usually used for single line matches. For multiline matching you may do better to look at sed.
Evo2.
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01-19-2010, 08:10 AM
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#5
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Member
Registered: Dec 2009
Posts: 41
Original Poster
Rep:
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Quote:
Originally Posted by evo2
Grep is usually used for single line matches. For multiline matching you may do better to look at sed.
Evo2.
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thx. any idea how?
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01-19-2010, 08:22 AM
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#6
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LQ Guru
Registered: Jan 2009
Location: Japan
Distribution: Mostly Debian and CentOS
Posts: 6,726
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There are oodles of sed tutorials on the web. Have a google (or wait for a sed expert to post the anser here).
Cheers,
Evo2
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01-19-2010, 12:31 PM
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#7
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Member
Registered: Jul 2005
Location: France
Distribution: Arch Linux
Posts: 540
Rep: 
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Code:
for file in $(find /test/upload/ -type f -name "*.xml" -print); do
if $(sed -n '/<cats>/ {n
p}' $file|grep -q Sports); then
echo $file
fi
done
This seems to answer your request, if I understood what you want to get, ie only the name of the files with the pattern :
<cats> immediately followed on the next line by the word Sports.
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01-19-2010, 01:25 PM
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#8
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LQ Guru
Registered: May 2005
Location: boston, usa
Distribution: fedora-35
Posts: 5,326
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maybe egrep -n "(sports|cats)" to get the line number.
then
if expr `grep -n sports` - `grep -n cats` -eq 1
then print the filename.
but there must be a simpler way.
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01-20-2010, 05:57 AM
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#9
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Member
Registered: Dec 2009
Posts: 41
Original Poster
Rep:
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Quote:
Originally Posted by berbae
Code:
for file in $(find /test/upload/ -type f -name "*.xml" -print); do
if $(sed -n '/<cats>/ {n
p}' $file|grep -q Sports); then
echo $file
fi
done
This seems to answer your request, if I understood what you want to get, ie only the name of the files with the pattern :
<cats> immediately followed on the next line by the word Sports.
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works well. thx..
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