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Old 01-19-2010, 04:00 AM   #1
guessity
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How to use find with two lines together?


I am trying to search for
Code:
<cats>
Sports
</cats>
how do i use the find command to search for <cats>Sports

The problem here is that the word Sports is in the next line of <cats> so I cant use -

Code:
find /test/upload/ -type f -name "*.xml" -exec grep -l "<cats>Sports" {} \; -print
How do I put the next line string? plz help..
 
Old 01-19-2010, 05:21 AM   #2
bigrigdriver
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Try this:
Code:
find /test/upload/ -type f -name "*.xml" -exec grep -l -A 1 -B 1 "Sports" {} \; -print
-A 1 print one line After the line containing Sports
-B 1 print one line Before the line containing Sports
 
Old 01-19-2010, 05:49 AM   #3
guessity
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thx but the file might contains a reference of word Sports anywhere so that command showed me all the files which ever contained the word sports irrespective of where the word is present.

the only unique reference is when sports is within <cats>

I just wanted to see the files which contains word withing <cats>





Quote:
Originally Posted by bigrigdriver View Post
Try this:
Code:
find /test/upload/ -type f -name "*.xml" -exec grep -l -A 1 -B 1 "Sports" {} \; -print
-A 1 print one line After the line containing Sports
-B 1 print one line Before the line containing Sports
 
Old 01-19-2010, 05:58 AM   #4
evo2
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Grep is usually used for single line matches. For multiline matching you may do better to look at sed.

Evo2.
 
Old 01-19-2010, 08:10 AM   #5
guessity
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Quote:
Originally Posted by evo2 View Post
Grep is usually used for single line matches. For multiline matching you may do better to look at sed.

Evo2.
thx. any idea how?
 
Old 01-19-2010, 08:22 AM   #6
evo2
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There are oodles of sed tutorials on the web. Have a google (or wait for a sed expert to post the anser here).

Cheers,

Evo2
 
Old 01-19-2010, 12:31 PM   #7
berbae
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Code:
for file in $(find /test/upload/ -type f -name "*.xml" -print); do
    if $(sed -n '/<cats>/ {n
                           p}' $file|grep -q Sports); then
        echo $file
    fi
done
This seems to answer your request, if I understood what you want to get, ie only the name of the files with the pattern :
<cats> immediately followed on the next line by the word Sports.
 
Old 01-19-2010, 01:25 PM   #8
schneidz
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maybe egrep -n "(sports|cats)" to get the line number.
then
if expr `grep -n sports` - `grep -n cats` -eq 1
then print the filename.

but there must be a simpler way.
 
Old 01-20-2010, 05:57 AM   #9
guessity
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Quote:
Originally Posted by berbae View Post
Code:
for file in $(find /test/upload/ -type f -name "*.xml" -print); do
    if $(sed -n '/<cats>/ {n
                           p}' $file|grep -q Sports); then
        echo $file
    fi
done
This seems to answer your request, if I understood what you want to get, ie only the name of the files with the pattern :
<cats> immediately followed on the next line by the word Sports.
works well. thx..
 
  


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