how to select a particular line from a file and assign it to a variable?

pdklinux79 · 06-17-2008, 02:13 PM

R 468bf89188632e67cd268d0b1a24833c10056b34 [13] 840 (13920) kind=7
R c7465b12162ae2c0a4601ba7895f154f38df1a69 17669
R 604775f0f7326e42e853359f64b2f5585d8f3551 24069
R df03a22135c735b59753cee0c8f4a8e4cac9f032 28528
R 5639c31a86ed9735a0c654510d1038620a85ab92 43007
R 519e896e36dff8dfd32a4bcfc2afac0d360ed1e4 67924

the above is how the file looks like. From the file i want 3rd row, 2nd column to be assigned to a variable.. can u let me know how to do it?

value=604775f0f7326e42e853359f64b2f5585d8f3551

thanks

forrestt · 06-17-2008, 02:21 PM

Try this:

Code:

#!/bin/bash
value=`head -3 | tail -1 | awk '{print $2}'`
echo $value

HTH

Forrest

pixellany · 06-17-2008, 02:25 PM

What have you tried?

You can get data by line # using SED, and then cut to give you the second field. AWK is also good for data that is in fields.

Example with SED:
sed -n '3p' filename|cut -d " " -f 2

Assign the whole thing to a variable name using:
var=$(command)
OR
var=`command` (backtics, not single quotes)

pdklinux79 · 06-17-2008, 03:03 PM

thanks .. both r working...

chrism01 · 06-18-2008, 07:21 PM

Yet another alternative

Code:

#!/bin/bash
value=`head -3 | tail -1 | cut -d' ' -f2`
echo $value