How to search date period in access log using grep

bilalcochin · 02-19-2010, 08:57 AM

Hello,

I have a three input day,month and year.
Currently i am using the following script to take the data.
Any grep advanced technique to avoid for loop?

#!/bin/bash
for day in $d
do
grep -h "$day/$month/$year" *access_log* >> output.txt
done

Thanks

MensaWater · 02-19-2010, 09:23 AM

Is day the word, abbreviation or the numeric? If the numeric does it get prepended with a 0 if it is the 1st through the 9th?

Instead of just d you could have d1, d2 & d3 - egrep (a/k/a grep -E) would then be the way to go:

Code:

#!/bin/bash
egrep -h "$d1|$d2|$d3"/$month/$year *access_log* >> output.txt

In the above the items in the quotes are separated by the pipe symbol which means "or" in this context.

pixellany · 02-19-2010, 09:24 AM

How is data getting into those variables? $d, $day, $month, $year

Does that script work as you have shown it?

Please show us a sample of the format used in the access log.

If you want an interactive script that takes data from the user, then you will have to have a loop.