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Old 04-30-2016, 07:53 AM   #1
bala2117
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Registered: Apr 2016
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How to run my own hello_world application on top of Linux kernel and how to convert my Kernel images into bootable image


I have compiled Linux kernel 4.5.2 for x86_64 machine and i got below set of files in /boot.
vmlinuz-4.5.2
System.map-4.5.2
config-4.5.2
initrdz-ramfs.img-4.5.2
bzImage
lib (directory)

Requirement:
===========
1. Where i need specify my own hello_world application?

2. How to convert compiled kernel images with application into bootable image (like USB bootable image). Also what are the files required among the above all to make it bootable image and how to do?

3. Then i need to boot my x86_64 machine through USB boot it should launch my hello_world application.

Kindly help me out with step by step procedure because I am not getting any clue.
 
Old 04-30-2016, 08:59 AM   #2
smallpond
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To just run your program, you can add an init job for it so that it runs when the system starts up. If you are trying to make it the only thing that runs on the box, then it is a little more complex.

A bootable system has 3 pieces:

1) Bootloader - after the platform firmware runs it starts the bootloader. Usually, you would use a standard bootloader like grub or grub2. The bootloader can have a menu to let you either boot your standard system or your test system.
2) Kernel - The kernel starts up and initializes drivers and then starts up a user space init program.
3) User space - Normally your user space is on disk, has shell, desktop and services and is mounted by a stock ramdisk image. In your case, if you just want to run one standalone program, you can do it all in the ramdisk. There are plenty of tutorials on the web on modifying it, like this one:

http://backreference.org/2010/07/04/...itramfs-files/

You would have to add your program, plus any libraries that it needs into the ramdisk image, and start it from the init script. For extra credit you can make it the init program so no script is needed, but I can't fit a proof of that in this margin.
 
  


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