Hi,

[ravi@ravi ~]$ cat text_file
biscuit 1

I want to replace the string "biscuit 1" with "biscuit 0" using a command or with a script.

I tried the following perl command:
The limitation here is.. it works only if the space between the "biscuit" word and the "number(0 or 1)" is exactly 6(as i use the 6 escape characters).

I want it to work..with unknown number of spaces between the word and the number.

Actually i need it vice versa.. i.e if the file is having "biscuit 0" the command/script should replace it to "biscuit 1" & if the file is having "biscuit 1"..the command/script should replace it to "biscuit 0".

Please help!!

Thanks,
Ravi

\s+ represents any non-zero amount of whitespace.

1 members found this post helpful.

Can you try awk:-

1 members found this post helpful.

Somehow, Got it
[ravi@ravi ~]$ cat text_file
biscuit 1
[ravi@ravi ~]$ cat code
#!/bin/sh
count=$(grep -i biscuit text_file | awk '{print $2}')
if [ "$count" == 1 ]; then
perl -pi -w -e 's/biscuit\s+\ 1/biscuit\t\t\t\t 0/g' text_file;
else
perl -pi -w -e 's/biscuit\s+\ 0/biscuit\t\t\t\t 1/g' text_file;
fi
[ravi@ravi ~]$ cat text_file
biscuit 1
[ravi@ravi ~]$ ./code
[ravi@ravi ~]$ cat text_file
biscuit 0
[ravi@ravi ~]$ ./code
[ravi@ravi ~]$ cat text_file
biscuit 1

---------- Post added 01-29-13 at 06:34 PM ----------

Thanks linosaurusroot, "\s+" helped me!!

perl -pi -w -e 's/(biscuit\s+) 1/\1 0/g' text_file