[SOLVED] How to replace "-\n>" to "->" in linux using sed
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I have done few attempts. But I didn't wrote it here because none of it worked.
I wrote this (which are obviously not correct):
head abc.txt | sed 's/-\n\>/-\>/g'
head abc.txt | sed 's/-\n>/->/g'
head abc.txt | sed 's/-\\n\>/-\>/g'
I am confused because when I wanted to enter "\n" between line, it is done quite easily by replacing ">" to ">\n" but reverse of it doesn't apply. That's why I am stuck.
It's tricky to get at the new line. Based on the small sample you gave, you could do it by checking for a dash at the end of each line and then, if one is found, appending the next line of input before doing the substitution.
Code:
sed -e '/-$/{ N; s/\n//; }' abc.txt
The /-$/ looks for a dash at the end of a line, then if one is found the N and s/// commands are executed.
I am confused because when I wanted to enter "\n" between line, it is done quite easily by replacing ">" to ">\n" but reverse of it doesn't apply. That's why I am stuck.
sed is stream oriented, so it gives you a record at a time - up to, but not including, the newline. Hence your problems. The solution provided is a simple way to overcome this if the data structure is known in advance.
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