How to print lines in csv file if 1 csv column field = "text". There are 10 column (;) in csv file
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Another vote for awk. If you are thinking in columns, you should often be thinking awk
Anyway, I just applied the grep CLI and manage to print the lines with specific column [2233].
Example source file:
Test result;unix timestamp;1234567890;2233;111;A;B;C;D;E
Test result;unix timestamp;1234567890;2235;111;A;B;C;D;E
No, you printed lines that had that number anywhere in the entire record. You could do it with grep, but you'll need some regex to eliminate the unwanted columns.
Using a mod of your example shows what syg00 is saying:
Code:
$ cat source.file
Test result;unix timestamp;1234567890;2233;111;A;B;C;D;E
Test result;unix timestamp;1223367890;2235;111;A;B;C;D;E
$ grep 2233 source.file
Test result;unix timestamp;1234567890;2233;111;A;B;C;D;E
Test result;unix timestamp;1223367890;2235;111;A;B;C;D;E
As you can see, the highlighted portions match but are not in the same columns.
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