How to print lines in csv file if 1 csv column field = "text". There are 10 column (;) in csv file
 

How to print lines in csv file if 1 csv column field = "xxxxx".

xxxxx = alphabet
xxxxx = numeric

There are 10 column in csv file:
For instant : Test result;unix timestamp;1234567890;2233;111;A;B;C;D;E

If csv column 5= 111, then print the line in source file

And have you made any effort to solve this yourself ?.

Welcome to LQ!
How about some actual data and not some arbitrary 'examples"?

i would look into the awk command.

^Ditto. But here are a couple of hints:
• awk
• field separator

Example:
Best regards,
HMW

Another vote for awk. If you are thinking in columns, you should often be thinking awk :)

This posting has been cancelled due to click post button unintentionally

Anyway, I just applied the grep CLI and manage to print the lines with specific column [2233].
Example source file:
Test result;unix timestamp;1234567890;2233;111;A;B;C;D;E
Test result;unix timestamp;1234567890;2235;111;A;B;C;D;E

grep 2233 [source filename] > output file
>Test result;unix timestamp;1234567890;2233;111;A;B;C;D;E

No, you printed lines that had that number anywhere in the entire record. You could do it with grep, but you'll need some regex to eliminate the unwanted columns.

Using a mod of your example shows what syg00 is saying:
As you can see, the highlighted portions match but are not in the same columns.