How to pass string variable as command parameter in shell script?

prasad1990 · 03-19-2015, 08:12 AM

Hello Friends,

I want to pass string variable with its value taken by user as command parameter in shell script, example below:-

echo "Enter New Password:="
read password

perl -pi -e
's/PASSWORD=.*?,/$password,/' abc.txt

Please let me know...
Thanks In advanced.

smallpond · 03-19-2015, 09:13 AM

How about:

Code:

CMD="perl -pi -e 's/PASSWORD=.*?,/"$password",/' abc.txt"
eval "$CMD"

drdvp · 03-19-2015, 05:04 PM

It should also work if you replace the single quotes with double quotes:
perl -pi -e "s/PASSWORD=,/$password," abc.txt

prasad1990 · 03-20-2015, 12:06 AM

Thanks to both of you.
There are multiple password field in file, and i want replace only one field out of multiple field. I used your solution but it replace all field.

What should i do?

jpollard · 03-20-2015, 09:05 AM

What is your program?

Parameters are stored in the argv array - and it is trivial to add something like "password=value" on the command line.

smallpond · 03-20-2015, 10:25 AM

What identifies the place in the file that you want to change?

prasad1990 · 03-23-2015, 12:48 AM

Actually, I have one file which contain connector with parameter,and want to replace only activate connector PASSWORD with this format NEW_PASSWORD=$password, password value accept by the user. for example below:

echo "Enter New Password:="
read password

perl -pi -e
's/PASSWORD=.*?,/$password,/' abc.txt

This is may abc.txt:-
# Activate connector
3[USER-ID=abacsd,PASSWORD=1234568,member-id=psudfsfd, etc..]

# DeActivate connector
;8[USER-ID=fdsdfgs,PASSWORD=45646224,member-id=psudfsfd, etc..]

Updated abc.txt
# Activate connector
3[USER-ID=abacsd,NEW_PASSWORD=1545644,member-id=psudfsfd, etc..]

# DeActivate connector
;8[USER-ID=fdsdfgs,PASSWORD=45646245,member-id=psudfsfd, etc..]

What should i do?