how to "ls" file starting with ./

simransab · 11-12-2009, 08:18 AM

When i do below command, i get the output:
linux% find ./work_work -type f
./work_work/123.log
./work_work/12212.log
./work_work/842150451_ETS160903_11062009.log
./work_work/bad_summary/-842150451_ETS160903_11062009.log
./work_work/bad_summary/ 123.log
./work_work/bad_summary/-123.log
./work_work/bad_summary/files_to_be_deleted.txt
./work_work/bad_summary/sc
./work_work/bad_summary/sc1
./work_work/bad_summary/sc2
./work_work/bad_summary/12-3.log
./work_work/bad_summary/12 212.log

When i do below command, i get the output:
linux% ls work_work/| grep -P "^( |-)"
123.log
-123.log
-842150451_ETS160903_11062009.log

How to get exactly like 1st out put (starting with ./) with second command (using ls)?

Urgent, thankful for those who can help me..

vinaytp · 11-12-2009, 08:46 AM

Quote:

Originally Posted by simransab

When i do below command, i get the output:
linux% find ./work_work -type f

Try with

Code:

ls -Rl | grep '^-' | grep "work_work"

Cheers !!!

pixellany · 11-12-2009, 08:55 AM

Urgent?? Why? Is anyone in danger or needing medical attention?

When you say "exactly like", I am **guessing** that you mean that you want the path from the current directory. I don't find a simple way of doing it, but it seems there should be one. Look at "man ls" and "man -k path"