How to grep sections of a line out and copy to new file

Leisurely Gentlemen · 05-08-2012, 02:45 PM

I have to grep out only parts of the lines and put into a new file

Lines look like this ie exampleA,exampleB,exampleC,exampleD

Now I only want exampleA,exampleB in my new file. How can I only select the first 2?

I hope this was clear enough. Thanks!

LG

Nermal · 05-08-2012, 02:57 PM

Code:

awk -F',' '{print $1","$2}' file_name

If you need to search then see this thread: http://www.linuxquestions.org/questi...ecords-942033/

Leisurely Gentlemen · 05-08-2012, 03:39 PM

Thank you.. Can you show me how to move it into a new file after this awk -F',' '{print $1","$2}' file_name

David the H. · 05-08-2012, 03:43 PM

Read the section in the bash guide on input/output for how to do file redirections.

http://mywiki.wooledge.org/BashGuide

Then go back to the beginning and read the whole thing.

And actually, cut would be more efficient for a simple job like this.

Code:

cut -d ',' -f 1-2 file > newfile

Leisurely Gentlemen · 05-08-2012, 03:44 PM

Quote:

Originally Posted by David the H.

Read the section in the bash guide on input/output for how to do file redirections.

http://mywiki.wooledge.org/BashGuide

Then go back to the beginning and read the whole thing.

And actually, cut would be more efficient for a simple job like this.

Code:

cut -d ',' -f 1-2 file > newfile

Thank you sir!