How to get an application name from its binaries Linux, Solaris, HPUX
 

Hi,

Please, is it possible? or is there a command one can use to get an application name/vendor from its binaries in Linux, Solaris and HPUX.

I had a situation once where sudo was installed on OEL 5 and anytime I ran "rpm - qa | grep sudo" it didn't return anything even though the binaries existed. I later found out that the rpm database was corrupt and had to fix it for it to work properly.

I am wondering if there is any other thorough process of checking binaries to know if an application is installed and possibly return the application

I will also like to get the vendor name for example there is sudo from Quest and thee is sudo from www.sudo.ws. I will like to be able to differentiate between these for my script to work

Thanks,
O

Not sure about sudo, however you can get the version or help on most commands using either --help --version, -h -v, /h /v, or /help /version. There should be some form of command line switches you can use to obtain this information.

Sure. You can use yum to find out what package it came from, then use rpm -Va to verify the contents of the package.

If something has changed (md5sum, permissions, etc) it will report the change/difference.

For example, if I change nano then check it, i get this:

If you want to avoid the pkg mgr, you could use 'find' and 'strings' .
Possibly also 'od' .

Not sure if that is what you ask for:
"which(1) is an external program used to search PATH for an executable. It behaves differently on different systems and you can't rely on a useful exit code; use (from most to least portable) ''command -v'' or ''type -P'' (to find the path) or ''hash'' (to check) instead. See http://mywiki.wooledge.org/BashFAQ/081"
And there is also "whereis"