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Old 03-15-2006, 10:56 AM   #1
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Registered: Mar 2006
Posts: 7

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How to get a files pathname into anoth script

I have this script that searches files checksums and then outputs them to another script, so basically the other script returns something like this:
#! /bin/sh
#rm 900150983cd24fb0d6963f7d28e17f72\ \ ./hendy.txt
#rm 900150983cd24fb0d6963f7d28e17f72\ \ ./hendy1.txt

i need to be able to include the pathname for hendy.txt and hendy.txt , is this possible???

so that the contents of the script looks like this:

#! /bin/sh
#rm /ramdisk/home/knoppix/tmp/hendy.txt
#rm /ramdisk/home/knoppix/tmp/hendy1.txt

The orignal script looks like this:
echo "#! /bin/sh" > $OUTF;
find "$@" -type f -print0 |
xargs -0 -n1 md5sum |
sort --key=1,32 | uniq -w 32 -d --all-repeated=separate |
sed -r 's/^[0-9a-f]*( )*//;s/([^a-zA-Z0-9./_-])/\\\1/g;s/(.+)/#rm \1/' >> $OUTF;
chmod a+x $OUTF; ls -l $OUTF

Old 03-16-2006, 03:59 AM   #2
Registered: Nov 2005
Distribution: xubuntu, grml
Posts: 451

Rep: Reputation: 37
what you want is to return the absolute path of files.
This script works: ./return-absolute-filename <somefile>
  if [ -d "$1" ] ; then   # Only a directory name.
    unset file
  elif [ -f "$1" ] ; then # Strip off and save the filename.
    dir=$(dirname "$1")
    file="/"$(basename "$1")
    # The file did not exist.
    # Return null string as error.
    return 1
  # Change to the directory and display the absolute pathname.
  cd "$dir" > /dev/null
  echo ${PWD}${file}
Here is my attempt at a one-liner to return the absolute path for files and dirs based on the script:
It does not like spaces in the filenames or directorynames ...
for i in `find -name "*"`;do dir=$PWD;cd $(dirname "$i");echo "$PWD/$(basename $i)";cd $dir; done

Last edited by muha; 03-16-2006 at 04:44 AM.
Old 03-16-2006, 09:33 AM   #3
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Registered: Nov 2005
Location: Belgium
Distribution: Red Hat, Fedora
Posts: 1,515

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find returns the absolute paths if you supply it an absolute directory to start with. It uses relative paths only if you give it one.
find ./ -type f #returns all files from the current directory down. Files in the output will all have a path
                #starting with "./" (hence a relative path).
find /etc -type f #returns all files below /etc. All outputted files will have paths starting with /etc/
                  #(absolute paths) because you supplied it the absolute path (/etc) to start with.
So, why bother recreating the absolute path for files, if find can supply it to you directly?

Second point: I think the provided script can be simplified too. For instance, it's not very useful to "write" a script based on the output of find (processed via some programs like sed and stuff).
Instead, make your script output in a format you know. Make a second script that calls the first one, captures it's output (via $(script) or `script` syntax, as muha shows with the find command) and treat each line of output separately. Seems much easier than what you're trying to do.


find "$@" -type f -print0 |
xargs -0 -n1 md5sum |
sort --key=1,32 | uniq -w 32 -d --all-repeated=separate |
sed -r 's/^[0-9a-f]*( )*//;s/([^a-zA-Z0-9./_-])/\\\1/g'
for i in ${files}; do
   echo "#rm ${i}";
   #you can now do what you want with the files...
Replace the "echo #rm ${i}" with "rm ${i}" if you want to actually remove the files.

But all in all, I have to say it's a nice way of eliminating duplicate files...
Old 03-21-2006, 07:29 AM   #4
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Registered: Mar 2006
Posts: 7

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Thanks for that guys, im still playing about with the scrpit, your input is greatly appreciated.


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