How to do multiple comaprison in a IF statement

pdklinux79 · 06-11-2008, 05:29 PM

Hi

How to accomplish multiple comaprison in a IF statement?

eg:

if [ $r = 'fail' ] or if [ $r = 'FAIL'] or if [ $r = 'Fail' ]
then
echo the state is $r. please note it
fi

im not able to accomplish this .. giving error.. please let me know how to do it.
thanks

Cuetzpallin · 06-11-2008, 05:40 PM

You could use "case" instead multiples if

See those links
http://steve-parker.org/sh/case.shtml

http://www.cyberciti.biz/nixcraft/li...ch03sec08.html

weibullguy · 06-11-2008, 07:08 PM

Try using regular expressions. Something along the lines of

Code:

if [[ $r == [Ff][Aa][Ii][Ll] ]]; then
	echo the state is $r. please note it
fi

chrism01 · 06-11-2008, 08:08 PM

OR:

if [[ $a -eq $b || $a -eq $c .... ]]

AND:

if [[ $a -lt $b && $a -gt $c .... ]]

armanox · 06-11-2008, 10:34 PM

Quote:

Originally Posted by weibullguy

Try using regular expressions. Something along the lines of

Code:

if [[ $r == [Ff][Aa][Ii][Ll] ]]; then
	echo the state is $r. please note it
fi

That's what I was going to say...