[SOLVED] How to copy-paste part of line within the file?
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in an editor called vi, start by vi <filename> --> place cursor below D of DPA --> <ESC> Key once (not necessarily) --> type "yw" (without quotes) which copies one word --> goto content line and place cursor where you want and type "p" (without quotes)
find *.txt -type f | while read file
do
awk '/<author>/{gsub(/<author>|<\/author>/,"");o=$0}/<content>/{$0=$0"\n"o}1' $file >$file.$$
mv $file.$$ >$file
done
I ended up with this error -
Code:
mv: missing destination file operand after `20099.txt.26848'
Try `mv --help' for more information.
mv: missing destination file operand after `2009.txt.26848'
Try `mv --help' for more information.
Any idea where I went wrong?
Quote:
Originally Posted by ghostdog74
use the redirection operator to redirect to a temp file, then use mv to rename it back to original
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