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Old 10-07-2007, 09:35 PM   #1
new_2_unix
LQ Newbie
 
Registered: Oct 2007
Posts: 26

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how to add "pipes" to a sed program file


hi,

i have a file named 'myfile' with the following contents:

Line one.
The second line.
The third.

i want to use sed to find the lines that contain the word 'The'.

This should result in:
The second line.
The third.

i then want to filter the above output to print the lines that do NOT contain the word 'third'.

This should result in:
The second line.

From the command line, I can do this with the command:
> sed -n '/The/p' myfile2 | sed -n '/third/!p'

My question is:
How do I do the same thing by creating a sed script file which will contain the sed commands above and allow me to run get the same output by executing the following:

> sed -n -f mySedScript myfile2

If I simply create a file 'mySedScript' and add the following to it:
/The/p
/third/!p

it does not work and gives me the following output which is wrong:
Line one.
The second line.
The second line.
The third.

Any ideas where I may be wrong? Thanks!
 
Old 10-07-2007, 10:02 PM   #2
jschiwal
LQ Guru
 
Registered: Aug 2001
Location: Fargo, ND
Distribution: SuSE AMD64
Posts: 15,733

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egrep might be the better choice for a program. Anyway, the second sed example could be done this way:
sed -n '/third/!p' inputfile >outputfile
The test is for lines that do not contain the word third, however, since you might want to exclude both 'third' and 'Third', this might work better:
sed '/third/d;/Third/d' inputfile >outputfile

There is a logical relationship that you might want to keep in mind, However, I'm not certain how to express it in a forum:
NOT ( A AND B ) = NOT A OR NOT B
Not A would be expressed on paper with a bar over the A.
 
Old 10-07-2007, 10:09 PM   #3
homey
Senior Member
 
Registered: Oct 2003
Posts: 3,057

Rep: Reputation: 59
This may work for you...
Code:
/The/{/third/!p}
 
  


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