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Old 10-25-2017, 02:05 PM   #1
anon3001
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Registered: Jan 2016
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How do I make i skip by 2's in Unix?


Hi,

In linux, you can do something like:

for i in {1..100..2}; do echo "hi $i times"; done

and it will do this:

hi 1 times
hi 3 times
hi 5 times
etc...

I'm trying this in Solaris 10, but it will interpret {1..100..2} literally, like this:

hi {1..100..2} times

Any idea how I can get this working in Solaris 10? Thanks!
 
Old 10-25-2017, 02:35 PM   #2
KenJackson
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I don't have access to Solaris, but the seq command seems to be ubiquitous, so it's probably there.
Code:
for i in $(seq 1 2 100); do echo "hi $i times"; done
 
Old 10-25-2017, 02:45 PM   #3
anon3001
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Thank you! Unfortunately, it doesn't look like this box has seq and I'm unable to install it. I'll keep check though
 
Old 10-25-2017, 02:52 PM   #4
MadeInGermany
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It's a bash feature.
In Solaris /bin/bash is bash version 3 (but Solaris has no seq program!)
Test the expansion with echo
Code:
echo {1..100..2}
 
Old 10-25-2017, 02:57 PM   #5
anon3001
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ok I got it. I just did:

for ((n=1;n<=10;n+=2)); do blah blah
 
  


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