LinuxQuestions.org - How can I modify this program to change it to a 2D array??

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How can I modify this program to change it to a 2D array??

I want it to be a 4x4 array the reads out 1-4 at random with repeating

EX)
4312
3124
1243
2431

My current program reads out a 1-10 at random without repeating
Can someone help me modify it?

Code:

#include <iostream>

#include <cstdlib>

#include <time.h>

using namespace std;

int main ()

{

    int A[10];

    srand (time(NULL) );

    int count = 0;

    while (count <10){

    int k = (rand() % 10) + 1;

    bool Placed = false;

    for (int i = 0; (i < count); i++){

    if (A[i] == k){

    Placed = true;

}

}

    if (!Placed){

    A[count] = k;

    count ++;

}

}





    for (int i=0; i<10; i++)

{

    cout << A[i] << " ";

}

    cout << endl;

    return 0;

}

[Wrong forum]

As this is C++, using static array is not necessary, use Vectors or Lists so you have a the find() function.

As for the 2D static array, a neat trick is to keep your existing code intact (but use 14 as size instead of 10). Then make a new array of size 4 and type int*. Place the newArr[0] = A, newArr[1] = newArr[1] = A+4; and so on. With that, you can have both a continuous and a 2D view of the same dataset. Again, it is a little trick, not something that would work in a pure algorithm point of view. It work because of the way C does static array pointer.

My apologies, I have reposted in another forum