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Linux/Unix newbie here with a quick and hopefully easy grep question. I have a log file I wish to go through and give me a count of the number of times a particular string is encountered; but, I want to be able to print back to the screen what it is I'm giving a number for, since I'm searching for several things. I have a few lines in my script file that say:
tail -100000 nameof.log | fgrep word | wc -l
If I run this it gives me a correct count, but just the number. How do I get it to let me print the word I'm searching for ahead of the count?
Thanks!
word_count=$(tail -100000 nameof.log) | fgrep word | wc -l)
echo word ${word_count}
or, you could do it all in the echo
Code:
echo word $(tail -100000 nameof.log) | fgrep word | wc -l)
The $( ) construct in bash allows you to run a command within a command. Very handy. Have a look at the Bash Guide for Beginners or the Advanced Bash Scripting Guide depending on how comfortable you are with Bash.
You could use the tee function, like this for example:
$ tail -100000 nameof.log | grep word | tee /dev/stderr | wc -l
That puts the matched line on stderr followed by the line count. If, instead, you want the information in a file, say "word.matched", something like this should work:
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