LinuxQuestions.org - grep patterns

- Linux - Newbie (https://www.linuxquestions.org/questions/linux-newbie-8/)

- - grep patterns (https://www.linuxquestions.org/questions/linux-newbie-8/grep-patterns-655686/)

I read the man pages for grep but I am still not sure how to do this simple task.

I want to look at log files that fall within July "Jul" AND have the string "BVCF" in them.

Is it possible to have more than one criteria in a grep command? If so, what is the correct syntax for this?

You can do

Code:

grep BVCF file | grep Jul

Hi.

Depending on your version of grep you may be able to do this:

Code:

#!/bin/bash -



# @(#) s1      Demonstrate multiple conditions for a pattern match.



echo

echo "(Versions displayed with local utility \"version\")"

version >/dev/null 2>&1 && version =o $(_eat $0 $1) grep

set -o nounset

echo



FILE=${1-data1}



echo " Data file $FILE:"

cat $FILE



echo

echo " Results:"

grep -E '(a.*b)|(b.*a)' $FILE



exit 0

Producing:

Code:

% ./s1



(Versions displayed with local utility "version")

Linux 2.6.11-x1

GNU bash 2.05b.0

grep (GNU grep) 2.5.1



 Data file data1:

a

b

c

cda

ab

ba

a plus b

b plus a



 Results:

ab

ba

a plus b

b plus a

In some situations you may need to use egrep -- see your man pages for details ... cheers, makyo