LinuxQuestions.org - [SOLVED] GREP help.. Urgent :(

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GREP help.. Urgent :(

Hi I am a newbie and need you expert's help.

I got a doc root (lets say /site/mysite/docs/) where i want to execute a recursive grep on all the directories and get a list of files in a file_list.txt

Now search is like this

1. Capture all files which has ""
2. Capture all files that has "" as well as "" BOTH
3. Ignore all file that has "" ONLY

I was able to get first two points done with following

find /site/mysite/docs/ -exec grep -ls '" ONLY.

Can someone help ?

Not sure that I've understood, however to exclude a match from your grep use -v, example

grep -something- | grep -v -e''

hope this helps

If you're using a recent version of GNU grep you can try its recursive capability (option -r) to avoid the find command. Anyway, you have to apply grep multiple times to include all the requirements. For example, to find out the files that have only the <!--#include virtual= pattern, you might do something like this:

Code:

while read file

do

  if ! grep -v '<!--#include virtual=' $file | grep -q '<!--#'

  then

    echo $file

  fi

done < <(grep -lr '<!--#include virtual=' *)

However, I would try something easier. Suppose you have the following awk code in a file called test.awk:

Code:

BEGIN {

  _[0] = "none"

  _[2] = "comment only"

  _[4] = "virtual only"

  _[6] = "both"

}



/<!--#/ {

  if ( $0 ~ /<!--#include virtual=/ )

    virtual = 4

  else

    comment = 2

}



END {

  print _[comment+virtual]

}

then you can run it recursively on all the files one at a time (using the find command), check the result and act accordingly. Example:

Code:

#!/bin/bash

while read file

do

  result=$(awk -f test.awk "$file");

  case "$result" in

    "none") echo $file has none ;;

    "comment only") echo $file has only comments ;;

    "virtual only") echo $file has only include virtual ;;

    "both") echo $file has both the patterns ;;

  esac

done < <(find /site/mysite/docs -type f)

Just an aside note: please don't use words as urgent in the thread title, since it's considered rude for people that voluntarily spend their time to answer questions and give help. Thank you.

You could probably combine like so with a small modification:

Code:

#!/usr/bin/awk -f



BEGIN {

  _[0] = "none"

  _[2] = "comment only"

  _[4] = "virtual only"

  _[6] = "both"

}



/<!--#/ {

  if ( $0 ~ /<!--#include virtual=/ )

    virtual = 4

  else

    comment = 2

}



END {

  print FILENAME,"has",_[comment+virtual]

}

Then you could just call it in your find:

Code:

find /site/mysite/docs -type f -exec ./test.awk {} \;

@ Everyone :Thanks a ton guys.. Let me try out the options and update you Gurus :)

@ colucix : Hey I am sorry for using word like "Urgent" .. this is my first post ever to any forum .. didn't know the etiquettes :) And thanks again for your help!!!

Saggu

Quote:

Originally Posted by snaravane (Post 4251528)

@ colucix : Hey I am sorry for using word like "Urgent" .. this is my first post ever to any forum .. didn't know the etiquettes :) And thanks again for your help!!!

Saggu

No problem! :)

Quote:

Originally Posted by grail (Post 4251421)

You could probably combine like so with a small modification:

Code:

#!/usr/bin/awk -f



BEGIN {

  _[0] = "none"

  _[2] = "comment only"

  _[4] = "virtual only"

  _[6] = "both"

}



/<!--#/ {

  if ( $0 ~ /<!--#include virtual=/ )

    virtual = 4

  else

    comment = 2

}



END {

  print FILENAME,"has",_[comment+virtual]

}

Then you could just call it in your find:

Code:

find /site/mysite/docs -type f -exec ./test.awk {} \;

Is there an option with find where I can ignore all binary files like .gz, .tar, .mp3, .gif etc ?

Quote:

Originally Posted by tirab (Post 4250890)

Not sure that I've understood, however to exclude a match from your grep use -v, example

grep -something- | grep -v -e''

hope this helps

hey i used your code and created a small script. it looks something like :

#!/bin/bash
ssi_list="/home/wwwdocs/ssi_list.txt"
for line in $(cat $ssi_list); do
grep '<!--#' $line | grep -v '<!--#include virtual='
if [ $? == "0" ]; then
echo $line >> ssi_list_refined.txt
fi
done

ssi_list.txt has list of all the files under /site/mysite/docs/ docroot !

its working.. thankyou for all your help :)