grep filter within line?
 

after using grep, I have the following line:
how to filter it out some more, so that only '49' is left?
thanks.

You can either pipe the output to another grep to match exactly the number at the end of the line and using the -o option to print out only the matching part:
To avoid the double grep command, you can use awk (or even sed) to match the Temperature pattern and extract only the information you need:

Or use sed:

This will eliminate the need for the first grep command, too.

You can also use 'cut' command:

$ echo ":temperature 49" | cut -d" " -f2
49

thanks all.

er, there are actually two lines with :Temperature, and I'd like to merge both numbers into one line.
is there a way to combine these two awk into single awk:

(I plan to use it in cron script and wish to reduce resource usage as much as possible)
or some better way?

Of course. Please show us the two lines and the desired result.

nevermind, I just found out how to do it:
awk '/:Temperature/{printf "%s ", $2}'


the two lines are these:
:Temperature 48
:Temperature 25

and output should be:
48 25


thanks.

That's it. You may want to add a terminating newline: