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Old 11-18-2016, 10:02 PM   #1
benjam1nrk
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Registered: Mar 2010
Distribution: CentOS
Posts: 24

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Unhappy Grep. Driving myself Insane.


I am running a command that looks like this:
Code:
./ssl-cert-check.sh -s oc.mydomain.com -p 443
It produces this output:
Code:
Host                                            Status       Expires      Days
----------------------------------------------- ------------ ------------ ----
oc.mydomain.com:443                        Valid        Feb 16 2017  90
I want to extract the "Days" from the output, 90 in this instance.

I have been unsuccessful using the following bash command
Code:
./ssl-cert-check.sh -s oc.visionsxtreme.com -p 443|grep '/([0-9])+$/m'
This regex appears to work in the web regex testers, but I cannot produce the desired results in the shell. What am I doing wrong, besides driving myself crazy?!

Thank you. Ben
 
Old 11-18-2016, 10:18 PM   #2
syg00
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Location: Australia
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Over thinking it way too much - try "grep -oE '[0-9]+$' ".

Last edited by syg00; 11-18-2016 at 10:21 PM. Reason: random bracket removed
 
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Old 11-18-2016, 10:23 PM   #3
benjam1nrk
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Registered: Mar 2010
Distribution: CentOS
Posts: 24

Original Poster
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Thank you, but running the following command still does not produce any output.
Code:
./ssl-cert-check.sh -s oc.mydomain.com -p 443|grep -oE '([0-9])+$'
 
Old 11-18-2016, 10:27 PM   #4
syg00
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The reason for things like that is generally whitespace at end of line - add it to your regex.
 
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Old 11-18-2016, 10:58 PM   #5
benjam1nrk
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Registered: Mar 2010
Distribution: CentOS
Posts: 24

Original Poster
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Thank you, I should have realized some white space may have existed. The following worked:
Code:
./ssl-cert-check.sh -s oc.mydomain.com -p 443|grep -oE '([0-9])+ *$'
I appreciate the help!
 
Old 11-19-2016, 01:05 AM   #6
grail
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A little longer, but this type of thing is well suited to awk:
Code:
./ssl-cert-check.sh -s oc.mydomain.com -p 443 | awk '/[0-9]/{print $NF}'
 
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