[SOLVED] Grep. Driving myself Insane.

benjam1nrk · 11-18-2016, 10:02 PM

I am running a command that looks like this:

Code:

./ssl-cert-check.sh -s oc.mydomain.com -p 443

It produces this output:

Code:

Host                                            Status       Expires      Days
----------------------------------------------- ------------ ------------ ----
oc.mydomain.com:443                        Valid        Feb 16 2017  90

I want to extract the "Days" from the output, 90 in this instance.

I have been unsuccessful using the following bash command

Code:

./ssl-cert-check.sh -s oc.visionsxtreme.com -p 443|grep '/([0-9])+$/m'

This regex appears to work in the web regex testers, but I cannot produce the desired results in the shell. What am I doing wrong, besides driving myself crazy?!

Thank you. Ben

syg00 · 11-18-2016, 10:18 PM

Over thinking it way too much - try "grep -oE '[0-9]+$' ".

benjam1nrk · 11-18-2016, 10:23 PM

Thank you, but running the following command still does not produce any output.

Code:

./ssl-cert-check.sh -s oc.mydomain.com -p 443|grep -oE '([0-9])+$'

syg00 · 11-18-2016, 10:27 PM

The reason for things like that is generally whitespace at end of line - add it to your regex.

benjam1nrk · 11-18-2016, 10:58 PM

Thank you, I should have realized some white space may have existed. The following worked:

Code:

./ssl-cert-check.sh -s oc.mydomain.com -p 443|grep -oE '([0-9])+ *$'

I appreciate the help!

grail · 11-19-2016, 01:05 AM

A little longer, but this type of thing is well suited to awk:

Code:

./ssl-cert-check.sh -s oc.mydomain.com -p 443 | awk '/[0-9]/{print $NF}'