getting expr : syntax error while executing script
 

getting an error for executing the following

for (( i = 1; i <= 9; i++ ))
do
for (( j = 1; j <= 9; j++ ))
do
tot=`expr $i +sj`
tmp=`expr $tot % 2`
if [ $tmp=0 ]
then
echo -e -n "\033[47m " ## for black color
else
echo -e -n "\033[40m " ## for white color
fi
done
echo -e -n "\033[47m"
echo "" ### print the new line ###
done

What you are trying to do ??
there are many mistakes in this script..

#here goes your syntax error

This will make whole your screen white unless you terminate the color code with \033[0m and produce no output. as every time the first condition become false. I dont know what you are trying to do ?

You should have spaces between your conditional operands.
And make sure you run Bash, not other shells.

Your arithmetic expressions could also be better done with (( )) as well. Run help let; help '(('.

Use correct operator '-eq' & double [[ ]]
http://tldp.org/LDP/abs/html/testcon...ml#DBLBRACKETS
http://tldp.org/LDP/abs/html/comparison-ops.html