[SOLVED] Get only Highest disk space

vanish78 · 05-14-2012, 08:47 AM

Hi There,
RHEL 5.6

I want a script that returns only the highest disk space. So far I have :

PHP Code:



#!/bin/sh 
df=`df -Pl | grep "^/dev" | awk '{print $5, $6}' | sed "s/%//"` 
echo "$df" | while read percent fs 
do 
    if [ $percent -ge 90 ] ; then 
       echo "$percent% -- Disk $fs" 
    fi 
done

Result :

PHP Code:



94% -- Disk /staging 
90% -- Disk /u02

So I only want 94% -- Disk /staging

Please help

blue_print · 05-14-2012, 09:04 AM

In your if loop change ge to gt

Quote:

if [ $percent -ge 90 ] ; then

to

Code:

if [ $percent -gt 90 ] ; then

colucix · 05-14-2012, 09:22 AM

Since you should sort the output and get only the first or the last line (depending on ascending or descending order) you might try something simpler as:

Code:

#!/bin/sh
#
df -Pl | sort -k5n | awk 'END{printf "%s -- Disk %s\n", $5, $6}'

In any case, what if two disks have the same percentage? Do you want to print them both?

vanish78 · 05-15-2012, 05:13 AM

Thanks guys, both your posts were very helpful.
@colucix : No, only one then.

Thanks!