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Old 05-29-2013, 12:06 PM   #1
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Get nth occurrence of two strings and replace it

I want to use sed command for this .

Fruit apple banana test
Fruit mango banana test
Fruit mango test

I want 2nd occurrence of Fruit mango banana Fruit

sed -n '/fruit/,/test/p;/test/q' filename > output

This command gives me first occurrence

Desired Output :

Fruit mango banana test (2nd occurrence of fruit and test)

Last edited by Mann_engg; 05-29-2013 at 12:44 PM.
Old 05-29-2013, 12:13 PM   #2
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Hi and welcome to LQ.

I'm not sure I understand what your desired output should be. Can you post a desired output string? What exactly do you want the 2nd occurrence of?
Old 05-30-2013, 05:56 PM   #3
David the H.
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Please use ***[code][/code]*** tags around your code and data, to preserve the original formatting and to improve readability. Do not use quote tags, bolding, colors, "start/end" lines, or other creative techniques. Thanks.

Your requirements are still not clear, and the explanation doesn't match the posted text. Do you want the second line that starts with Fruit and ends with test? If so, I think this will do what you want:

sed -n '0,/^Fruit.*test/d ; /Fruit.*test/{p;q}' input.txt
It deletes the first match, then prints the next one and exits.

awk is actually a bit easier here, logically, if slightly longer, and you can use it to match any arbitrary entry. Just load the matching lines into an array and print the one you want.
awk '/^Fruit.*test/ { a[++n]=$0 } n==2 { quit } END { print a[2] }' input.txt
The n==2 test ends the processing after you've reached the line you're interested in.

Last edited by David the H.; 05-30-2013 at 06:00 PM. Reason: minor code alteration


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