function slideSwitchtop() { var $active = $('#slideshowtop IMG.active'); if
This is the error message:
Parse error: syntax error, unexpected ';'..thanks.
// Display Code in Profile
$query = "SELECT * FROM user WHERE user_id='$user'";
$result = mysql_query($query);
while($row = mysql_fetch_assoc($result))
echo "UserID : {$row['user_id']} <br>" .
"Password : {$row['password']} <br>" .
"First Name : {$row['fname']} <br>" .
"Last Name : {$row['lname']} <br>" .
"Age: {$row['age']} <br>" .
"Gender : {$row['gender']} <br>" .
"Course: {$row['course']} <br>" .
"Year Level: {$row['ylevel']} <br>" .
"Email Add : {$row['email']} <br>" .
"Contacts : {$row['contact']}; <br>" .
?>
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