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A better option would be to use the positional parameter $@ in my opinion.
Quote:
@
Expands to the positional parameters, starting from one. When the expansion occurs within double quotes, each parameter expands to a separate word. That is, "$@" is equivalent to "$1" "$2" .... If the double-quoted expansion occurs within a word, the expansion of the first parameter is joined with the beginning part of the original word, and the expansion of the last parameter is joined with the last part of the original word. When there are no positional parameters, "$@" and $@ expand to nothing (i.e., they are removed).
so your script would change to:
Code:
for i in $@
do
ssh root@$i "cd /local/0/home;mkdir -p $1/test"
done
Try that out and let us know if it works for you.
Kind regards,
Eric
EDIT: beaten by the newly baked mod :-) but with another solution.
The OP needs to cycle through positional parameters from the 2nd to the last one, so that your scripts need a little modification. Here is another solution with indirect reference:
Code:
for i in $(seq 2 $#)
do
ssh -n root@${!i} "cd /local/0/home; mkdir -p $1/test"
done
Regarding the -n option of ssh, maybe in this case its not necessary, since the loop doesn't get the standard input (indeed the positional parameters are passed to the script itself, not to the loop). Sorry for the confusion.
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