[SOLVED] find maxdepth and print only the maxdepth matches

cli · 06-09-2013, 11:23 AM

Hi All,
I have directory structre as below

Code:

$ tree /tmp/OS/ -d
/tmp/OS/
|-- Linux
|   |-- Debian
|   |   `-- test
|   |-- Fedora
|   |-- RedHat
|   `-- Suse
|       `-- test1
|           `-- test2
`-- Windows
    |-- Vista
    `-- XP

11 directories

Now I wanted print only upto 3rd subdirectory inside /tmp. For example I wanted to get output as only below

Code:

/tmp/OS/Linux/Debian
/tmp/OS/Linux/Fedora
/tmp/OS/Linux/RedHat
/tmp/OS/Linux/Suse
/tmp/OS/Windows/Vista
/tmp/OS/Windows/XP

and wanted hide everything which are lesser than or greter than 4th directory. For that I ran

Code:

$ find /tmp/OS/ -maxdepth 2 -type d | sort
/tmp/OS/
/tmp/OS/Linux
/tmp/OS/Linux/Debian
/tmp/OS/Linux/Fedora
/tmp/OS/Linux/RedHat
/tmp/OS/Linux/Suse
/tmp/OS/Windows
/tmp/OS/Windows/Vista
/tmp/OS/Windows/XP

Since I am getting output as above how can I hide these below?

Code:

/tmp/OS/
/tmp/OS/Linux
/tmp/OS/Windows

Please help me.

Firerat · 06-09-2013, 11:49 AM

something like this would work for your example

Code:

find /tmp/OS/*/* -maxdepth 0 -type d

cli · 06-09-2013, 01:03 PM

Quote:

Originally Posted by Firerat

something like this would work for your example

Code:

find /tmp/OS/*/* -maxdepth 0 -type d

Thanks a lot.

Beryllos · 06-09-2013, 05:11 PM

Alternatively, you could use -mindepth:

Code:

find /tmp/OS/ -maxdepth 2 -mindepth 2 -type d

David the H. · 06-11-2013, 12:36 PM

This particular job could also be done with shell globbing.

Code:

printf '%s\n' /tmp/OS/*/*/