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fbfd1338

10-22-2005 12:23 AM

File count with script?

I am trying to write a small script that will rename my digital camera photo's the have weird names like DCD 20040925 to a simpler naming of just a 4 digit numbering system ie. 0001, 0002, 0003.jpg, etc. I was suggested to me that I do a file count of the folder that the pics are in, then have the names changed to progress up to the file count? Wel I am having trouble finding how to obtain a file count, and curious if there may be a better way to do this? Thanks a bunch.

-Kevin

Dark_Helmet

10-22-2005 12:53 AM

One possible way is to run the following command:

Code:

ls -1 | wc -l

Just to be thorough, that's a one (1) for the option to ls.

That will count how many things are in a directory. "Things" includes regular files and directories. If there are directories mixed with the images, I would suggest reading up on the find command (man find) with specific attention to the "-type" and "-maxdepth" options.

eddiebaby1023

10-22-2005 08:55 AM

Quote:

Originally posted by Dark_Helmet
One possible way is to run the following command:

Code:

ls -1 | wc -l

Just to be thorough, that's a one (1) for the option to ls.

That will count how many things are in a directory. "Things" includes regular files and directories. If there are directories mixed with the images, I would suggest reading up on the find command (man find) with specific attention to the "-type" and "-maxdepth" options.

ls will automatically infer -1(one) if its output isn't routed to a terminal, so ls | wc -l is equivalent (and shorter). Try:

Code:

ls 

ls | cat

to see the difference.

homey

10-22-2005 09:24 AM

Here is something which may get you started. You should try it on a practice folder first.

Code:

#!/bin/bash

#Example: ./test /home/images

usage()

{

  echo "Usage: $0 Directory_Name"

  echo "Example: ./test /home/images"

  exit 1;

}



test -d "$1" || usage



dir="$1"



mkdir $dir/tmp 2> /dev/null



ls $dir | \

while read i ; do

  n=$(( $n + 1 ))

  j=`echo "$i" | awk -F. '{print $2}'`

  mv -v "$dir/$i" "/tmp/file$n.$j"

if [ $n -lt '10' ]; then

  mv "/tmp/file$n.$j" "/tmp/file00$n.$j"

elif [ $n -ge '10' -a $n -lt '100' ]; then

  mv "/tmp/file$n.$j" "/tmp/file0$n.$j"

fi

done

find /tmp -type f -name 'file*' -exec mv -v {} $dir \;

fbfd1338

10-23-2005 03:02 AM

Homey.....
Thank you for the help, with a few minor alterations to the script I was able to use alot of what you gave me and it works perfect.

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