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Old 11-28-2010, 06:20 AM   #1
stf92
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Registered: Apr 2007
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Erasing from home up to first blank as I type at the prompt.


GNU bash 3.1.17

Hi:
I say there must be, in bash, a keystroke combination that does this: I type say, two words at the prompt. Then I press HOME. And now, holding down some control key, I press a key that erases from current cursor position up to the first blank (the space between the two words). If I am right, which is the key combination? You could as well refer me to the bash manual section where the different combinations, one of them a control key are listed. Thanks in advance.
 
Old 11-28-2010, 06:53 AM   #2
ntubski
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It depends on what you think a word is. M-d (ALT+d or ESC d) will do kill-word but a word is defined as a sequence of [a-zA-Z_] so (! represents the cursor)
Code:
$ !command-one command-two
# press M-d, now you have
$ !-one command-two
There isn't a forwards equivalent to C-w (unix-word-rubout).
See Commands for Killing.
 
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Old 11-28-2010, 07:31 AM   #3
stf92
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Registered: Apr 2007
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Yours has been a most useful post to me. I see what you meant by "my definition":
Code:
aaa bbbbbbbbb     two M-d to erase all
aaa/bbbbbb        two M-d to erase all
To bash, <space> and '/' both of them are separators, I see. Thanks a lot.
 
  


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