Hello Team,

I need cronjob syntax to schedule job for every 2 week(biweekly).
for example, suppose i executed job today(18 Nov) then next job should execute on 2 Dec on 10 AM.

I tried with below syntax but does not work out.
note: running on ubuntu system.

* 10 * * 5/2
* 10 7-14,21-28 * 5

Please help me here.

i think you will need to cron it weekly and handle the bi-weekly logic in the program being run.

i would have it touch a file when it ends and create an if statement to check for the existence of said file and if it does exist then delete it and end; else continue.

I dont have a Linux session to hand at present but I would expect the 1st example to be invalid

Both are requesting to run every minute between 10:00 and 10:59 which I don't think is what you want

Fields are:

Minutes
Hours
Dayofmonth
Months
Dayofweek

Suggesting your 2nd option is closer to what you are asking for

using google and your question "Cronjob for biweekly" I found these,

http://serverfault.com/questions/404...weekly-cronjob

http://stackoverflow.com/questions/1...y-twice-a-week

http://www.unix.com/unix-for-advance...ough-cron.html

1 members found this post helpful.

It would be overkill if this is all you need to do. But if you find yourself doing this sort of thing a lot, and it's appropriate for your environment, you might be interested in remind. It has an entire language built for scheduling things, and you can view reminders as a calendar using wyrd. It can also execute arbitrary scripts instead of reminding you of things, though I'm not sure I'd give it root privileges. Here's an example from the man page:

For example, suppose you get paid every second Wednesday, and your last payday was Wednesday,28 October, 1992. You can use:
REM 28 Oct 1992 *14 MSG Payday

Also, anacron and (I would assume) systemd timers could be used for this.