i have done this before when setting up squid but can not remember or find the command.
I would like to create directories with owners/permissions that stick. By that i mean:
mkdir /store
chown newowner /store
chmod 770 /store
mkdir /store/1
mkdir /store/2

is it possible (umask?)for /store/1 and /store/2 to end up with newowner and 770 during the mkdir process? Is there a command that will tell /store that every directory created under /store should have newowner and 770?

I have been lurking for a while and found this forum to be very helpful.

Thanks ahead.

Do the mkdirs first, the use the -R switch (recursive) on the chmod & chown cmd. Don't forget the grp owner eg
chown -R owner:grp somedir

thanks for the quick response.

I was looking for something besides a recursive. I remember a swith or a sticky permission of some sort that would say that anything under that certain directory would inherit permissions and owner from the parent.

thanks anyway.

Sounds like your confusing it with the 'sticky' bit. See section 6 here: http://www.zzee.com/solutions/unix-p...s.shtml#setuid

Yes. The owner of a directory can set the suid and sgid of the directory. Files created by other users will then inherit the owner and group of the parent directory. The permissions on a new file or directory will be masked according to your umask setting.

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update:
I tried it out with a directory I created on in my home directory. I created it as root and gave it 7777 permissions. A file I created there as a regular user had the group ownership of root but not the ownership. A directory I created there had the group of root but I was the owner.
There may be a capability setting that doesn't allow suid on directories; and maybe there's a good reason why.
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If you have a directory structure that you want to create, you could use brace expansion to do it, and then use chown and chmod recursively.

mkdir -p store/{1..10}
This will create directory "store" with ten subdirectories "1".."10".