LinuxQuestions.org - [SOLVED] create script by spliting filenames

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create script by spliting filenames

hello (again!)

folks i am trying to write a bash script to restore some files from a bunch of archives.

the archive are named as follows:

Code:

ls

vzdump-qemu-201-2011_08_19-18_09_13.tgz

vzdump-qemu-202-2011_08_19-18_11_45.tgz

vzdump-qemu-203-2011_08_19-18_14_05.tgz

vzdump-qemu-3321-2011_08_19-18_16_37.tgz

vzdump-qemu-7501-2011_08_19-18_18_32.tgz

vzdump-qemu-99000-2011_08_19-18_31_24.tgz

vzdump-qemu-99101-2011_08_19-17_58_40.tgz

vzdump-qemu-99201-2011_08_19-18_01_07.tgz

vzdump-qemu-99501-2011_08_19-18_02_28.tgz

to run the tool that i need; i require to know the ID of this file.

for the first file (vzdump-qemu-201-2011_08_19-18_09_13.tgz)
this ID is 201

so i need to split/cut out the filename and get this ID for each file.

i have tried to find the solution - but i have not found many articles that described what they were doing - and instead i found a lot of pieces of bash coding that did something that i did not understand.

many thanks,

Hello nicolasdiogo,

I'd use Perl for this:

Code:

#!/usr/bin/perl



use strict;

use warnings;



opendir(TGZFILES, ".") or die "doesn't work $!\n";

my @file;

while (readdir TGZFILES) {

  if ($_ =~ m/\.tgz/) {

      @file = split "-", $_;

      print "id: ", $file[2], "  filename: ", $_, "\n";

  }

}

Markus

For me awk is the God, so here is my solution (acording to the name format you have provided).

ls vz*|awk '{print substr($1,13,length($1)-36)}'

just to help clarify for everyone: is the ID always the first 3 digits? or the numbers in between the 2nd dash and the 3rd dash? (ex: 99501 for the last file)

I think it depends what else you might need to do, but if you were to use ls and awk as suggested by rodrifra, I think this would be easier:

Code:

ls vz* | awk -F- '{print "ID:",$3}'

If it is a script your after to also do other things, bash could also give it a whirl:

Code:

for file in vz*

do

    set -- ${file//-/ }

    echo "ID: $3"

done

Not only easier, it is much better your way grail.

Regards.

Code:

for file in vz*

do

    echo $file | cut -d'-' -f3

done

thanks a lot Chris,

i finished the script using your suggestion many thanks

No worries; glad I could help :)