[SOLVED] Count occurrence of character in field and print in a new field

Trd300 · 03-15-2012, 12:44 AM

%%%%%

grail · 03-15-2012, 03:10 AM

Something like:

Code:

awk 'BEGIN{OFS="|"}{if(NR == 1)$6 = "Field6";else $6 = 0}NR > 1 && $4 ~ /x/{$6 = split($4,_,"x") - 1}1' file

Trd300 · 03-15-2012, 04:36 AM

Thanks grail !

I see what you mean. It is a bit like using the character I am looking for as FS and count the number of field.

Like:

Code:

awk 'BEGIN {FS="x"} {print $0, NF-1}' file

Except that the split option restricts the move to the field only.
I didn't know that the split option returns the number of array by default.

Thanks again grail !

Trd300 · 03-20-2012, 03:51 AM

error

grail · 03-20-2012, 04:32 AM

error???? Would you like to provide more information?

Trd300 · 03-21-2012, 07:57 PM

No no, it works !

I didn't write on the good thread, my mistake !