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Checking if a directory exists within makefile

Hi,

I'm having trouble with a makefile I'm trying to write that uses a bash command to test for the existence of a certain directory.

Here is the makefile:

Code:

DEBUG=

OUT=a.out

LIBS=-lSDL -lSDL_image

OBJECTS=Main.o

BIN=bin



default: $(BIN) $(OBJECTS)

    g++ -o $(OUT) $(DEBUG) $(addprefix $(BIN)/, $(OBJECTS)) $(LIBS)



$(BIN):

    if [ ! -d "./$(BIN)" ];then 

        mkdir $(BIN) 

    fi



Main.o: Main.cpp

    g++ -c $(BIN)/$@ -c $<

Here is the output I get when I run make in the console:

Code:

josh@josh-Dell-XPS420:~/Desktop/Diminisher/Version 1$ make

if [ ! -d "./bin" ];then 

/bin/sh: 1: Syntax error: end of file unexpected

make: *** [bin] Error 2

josh@josh-Dell-XPS420:~/Desktop/Diminisher/Version 1$

Any ideas? I'm not very good with Makefile or Bash so it's probably something obvioius I'm missing.. I just can't find it.

Try to store the full path of bin in the variable BIN like:

Quote:

BIN="/path/to/bin"

you have mentioned the relative path.

And also in the script mention like this:

Quote:

if [ ! -d $(BIN)]

Quote:

Originally Posted by divyashree (Post 4685791)

Try to store the full path of bin in the variable BIN like:

Er, no. The path must be relative to the project directory (what happens if the Makefile is moved to another directory?)

The problem is that make assumes each line is a separate command. If you want a command to span multiple lines, you need to backslash escape them (except for the last one, of course), like so:

Code:

$(BIN):

        if [ ! -d "./$(BIN)" ];then    \

                mkdir $(BIN);          \

        fi

Note the semi-colon after the mkdir, this is needed as all the backslashed lines are joined together into one line.

I tried the backslashes because that thought came into my mind.. just forgot the semicolon. Thanks lej.