Check data and run script
 

I would like to write a script to do such thing , if a directory have file that the extension is today (yymmdd), then do a specific action , I will run a cron job to run this script .

for example

oday is 2nd , if the directory have files which file name are abc.121102 and def.121102 , then echo the file name , so the output is abc , def


tomorrow is 3rd , if the directory have files which the file name are xxx.121103 and yyy.121103 , then echo the file name , so the output is xxx , yyy

can advise how to it ?

thanks.

In the approximately nine years you've been with us you've posted over 600 threads and often about scripting. By now you should put in some effort and make it a habit to post what you have come up with without being asked.
TIA

Yes...read the advice given to you over the past NINE YEARS, and try to actually APPLY THAT KNOWLEDGE AND LEARN SOMETHING
http://www.linuxquestions.org/questi...lp-4175432449/
https://www.linuxquestions.org/quest...er-4175413626/
https://www.linuxquestions.org/quest...te-4175413358/
https://www.linuxquestions.org/quest...column-944377/
https://www.linuxquestions.org/quest...script-946113/

You've been pointed to shell scripting tutorials many, MANY times...you need to actually READ one.