[SOLVED] Change work directory in a shell script doesn't works

kerontide · 04-05-2017, 10:45 AM

Hi,

I develop my first time a little scrip shell for search a word inside of files on a folder, files can be in ascii in ebcdic can be compressed ... and works but only works if I execute the script inside the same folder who has the files.

So I decide to implement the change directory but doesn't works

is my first script so please don't be hard with me

Why when I execute the line:

cd $origin

I see with "pwd" command that I am in the correct path but script doesn't take care about the files of the origin path??

I hope I explain me well.

thanks a lot in advance.

Code:

#!/bin/bash
#
# Search.sh "search pattern;origin path;destiny result path(optional)" *
#
# Search.sh "46117;/home/sboixg/Descargas;/home/sboixg/Descargas/test" *  --> that means search 46117 into /home/sboixg/Descargas and copy the files who match with pattern into /home/sboixg/Descargas/test
#
# Search.sh "46117;/home/sboixg/Descargas;" * --> that means search 46117 into /home/sboixg/Descargas and print the result files
#
# Program has 4 parms:
# value you want to search 
# path origin where you want to search 
# path for copy the found records (optional)
# files filter for all *
#


parameters=$1 ; shift

workdir=$(dirname "$0")
echo "$workdir" - develop path

aux="$parameters"

IFS=';' read -a aux1 <<< "${aux}" #split ; in array

pattern=${aux1[0]}
origin=${aux1[1]}
aux2=${aux1[2]} 
dest=${aux2// }


listado=0
if [ -z "$dest" ]
then
    listado=1
fi

cd $origin
echo Confirm SEARCH IN the path BELOW - Y/N ?
pwd
read conf
if [ $conf != "Y" ]
then
    exit
fi

echo Working...please wait.
if [ $listado != 1 ] ; then
    if [ ! -d "$dest" ] ; then # check if folder destiny exist, if not create it.
      mkdir "$dest" 
    fi
fi

total=0
for x do
  isFile=$(file $x | cut -d\  -f2)
    if case "$isFile" in
            "gzip") < "$x" gzip -dc 2>/dev/null | dd conv=ascii 2>/dev/null | grep -q -e "$pattern" 2>/dev/null
                    if [ $? -ne 0 ] # capture the error
                     then 
                      < "$x" gzip -dc 2>/dev/null | grep -q -e "$pattern" 2>/dev/null
                    fi;;

        "ISO-8859") < "$x" dd conv=ascii 2>/dev/null | grep -q -e "$pattern" 2>/dev/null
                    if [ $? -ne 0 ]
                     then 
                      < "$x" grep -q -e "$pattern" 2>/dev/null
                    fi;;

            "data") < "$x" dd conv=ascii 2>/dev/null | grep -q -e "$pattern" 2>/dev/null
                    if [ $? -ne 0 ]
                     then 
                      < "$x" grep -q -e "$pattern" 2>/dev/null
                    fi;;

           "ASCII") < "$x" grep -q -e "$pattern" 2>/dev/null
                    if [ $? -ne 0 ]
                     then 
                      < "$x" grep -q -e "$pattern" 2>/dev/null
                    fi;;

                 *) < "$x" grep -q -e "$pattern" 2>/dev/null;;
        esac
    then
        total=$((total+1))
        if [ $listado = 1 ]
         then
            echo "$x"
         else
            cp "$x" "$dest" 
        fi
    fi
done

if [ $listado != 1 ] ; then
    echo "$total" files copied to the destiny path "$dest" who contain pattern "$pattern" 
    ls -l "$dest"
fi
exit 1

kerontide · 04-05-2017, 11:02 AM

I will try to clarify my problem

I have huge volume of files in path A (I have a thousand of paths with thousand of files) and I want that my script (that seems works) stay in a folder like /Tools and who need to search a file with a value inside can use it.

then my script has these parameters:

1. word you are looking for
2. origin path (where the files are stored)
3. destiny path (optional parameter if doesn't comes list the files founded if comes copy there the files) [works fine]

problem is if I execute the script in /Tools and I set the parameters like this:

kerontide@cinnamon /Tools $ Search.sh "3345667;/bin/arch/A;" *

script take the files for search of the folder /Tools instead the folder /bin/arch/A

this is why I ask why my "cd" command doesn't works

Keith Hedger · 04-05-2017, 11:19 AM

dont use ';' as a sepetrator and remove the IFS ... code, if your params include spaces then use quotes, also please use [code] ... [/code]tags around your code to make it readable, see:
http://www.linuxquestions.org/questi....php?do=bbcode

kerontide · 04-05-2017, 11:25 AM

Quote:

Originally Posted by Keith Hedger

dont use ';' as a sepetrator and remove the IFS ... code, if your params include spaces then use quotes, also please use [code] ... [/code]tags around your code to make it readable, see:
http://www.linuxquestions.org/questi....php?do=bbcode

thanks about the code, now is ok,

about your suggestion...why I can't not use ";" ? it works fine, do you think is related to my problem? if I use other separator will works fine?

thanks.

Keith Hedger · 04-05-2017, 11:50 AM

basically if you dont have any pressing need to change the default separator (space) then dont, especially when you are first learning scripting you will just cause your self problems as changing IFS can cause subtle problems that are difficult to diagnose, but simply why cause yourself more problems than you need to.

kerontide · 04-05-2017, 12:30 PM

I use IFS for split the parameters, because I want to use as optional the third parameter.

Which is the command that I can use for split values into an array for evaluate them?

Can I evaluate a parm null?

Thanks in advance

kerontide · 04-05-2017, 01:43 PM

Quote:

Originally Posted by Keith Hedger

basically if you dont have any pressing need to change the default separator (space) then dont, especially when you are first learning scripting you will just cause your self problems as changing IFS can cause subtle problems that are difficult to diagnose, but simply why cause yourself more problems than you need to.

I continue without know why I can use "cd" inside my script and if I use what you comment doesn't work also. Now without the "splited paramter" works more strange.

for example I delete the IFS and use the "natural" parameters

Code:

#!/bin/bash
#
# ./Search.sh "search pattern;origin path;destiny result path(optional)" *
#
# ./Search.sh "46117;/home/sboixg/Descargas;/home/sboixg/Descargas/test" *  --> that means search 46117 into /home/sboixg/Descargas and copy the files who match with pattern into /home/sboixg/Descargas/test
#
# ./Search.sh "46117;/home/sboixg/Descargas;" * --> that means search 46117 into /home/sboixg/Descargas and print the result files
#
# Program has 4 parms:
# value you want to search 
# path origin where you want to search 
# path for copy the found records (optional)
# files filter for all *
#

#parameters=$1 ; shift

pattern=$1
origin=$2
dest=$3 ; shift


workdir=$(dirname "$0")
echo "$workdir" desarrollo


listado=0
if [ -z "$dest" ]
then
    listado=1
fi


printf '%s\n' "$listado"
printf '%s\n' "$pattern"
printf '%s\n' "$dest"
printf '%s\n' "$origin"

doesn't works, when I print $dest and I let this parm in blank return a filename in the folder and also I set other folder as origin and doesn't works, well works worst

Code:

kerontide@cinnamon ~/Descargas $ bash Search.sh NAD\+CZ\+000916800 /home/kerontide/Descargas/test *
. desarrollo
0
NAD+CZ+000916800
0011823513.9b18e780-b024-11e5-a5c2-27140a1468a0.received
/home/sboixg/Descargas/test
Confirm SEARCH IN the path BELOW - Y/N ?

$pattern = NAD+CZ+000916800
$dest=0011823513.9b18e780-b024-11e5-a5c2-27140a1468a0.received ¿? I don't fill this parameter is in blank, is this cause by the "*"?
$origin=/home/sboixg/Descargas/test

kerontide · 04-05-2017, 02:16 PM

finally I use the "natural" parameters but I don't understand why if I only put 2 parm system answer me with the first file name, this is the most strange

but finally I think I use it well checking this third parameter:

Code:

#!/bin/bash

pattern=$1
origin=$2
dest=$3 

aux2="$dest"
dest=${aux2// }

workdir=$(dirname "$0")
echo "$workdir" - develop path


listado=0
if [ -z "$dest" ]
then
    listado=1
fi

m=`expr substr "$dest" 1 1`
if [ $m != "/" ]
then
    listado=1
fi

but I still have the problem when I run the script for check files inside other path different of the script path, the pwd return script is in the correct "origin" path but when run they start to list the files on the script path, why this behavior?

thanks a lot in advance.

kerontide · 04-05-2017, 02:51 PM

I think I have it, it seems my error was only put * at the end, it seems is necessary to put the entire path

and works with IFS also

thanks a lot!!

I will put here the last version of the code in few minutes.

kerontide · 04-05-2017, 03:45 PM

final code that works perfect!!!! thanks a lot for your help:

Code:

#!/bin/bash
#
# ./Search.sh "search pattern;destiny result path(optional)" *
#
# Program has 3 parms:
# value you want to search 
# path for copy the found records (optional)
# path origin where you want to search with * for all or *.gz or...
#

#get parameters
parameters=$1
workdir=$(dirname "$2")

#set working directory
origin="$workdir"

#split parameter $1 into array for check values pattern & optional destiny path
aux="$parameters"
IFS=';' read -a aux1 <<< "${aux}" #split ; in array

pattern=${aux1[0]}
aux2=${aux1[1]} 
dest=${aux2// } #trim blank chars


listado=0
if [ -z "$dest" ] #if $dest is null means you want list the files only
then
    listado=1
fi

#check the search origin path
cd $origin
echo 'Confirm SEARCH IN the path --> '"$origin" '(Y/N) ?' 
read conf
if [ $conf != "Y" ]
then
    exit
fi

echo Working...please wait.
if [ $listado != 1 ] ; then
    if [ ! -d "$dest" ] ; then # check if folder destiny exist, if not create it.
      mkdir "$dest" 
    fi
fi

total=0
for x do
  isFile=$(file $x | cut -d\  -f2)
  #printf '%s\n' "$isFile"
  #printf '%s\n' "$x"
    if case "$isFile" in
          "cannot") != "cannot" 2>/dev/null;; #first movement the pattern, don't take care

            "gzip") < "$x" gzip -dc 2>/dev/null | dd conv=ascii 2>/dev/null | grep -q -e "$pattern" 2>/dev/null
                    if [ $? -ne 0 ] # capture the error
                     then 
                      < "$x" gzip -dc 2>/dev/null | grep -q -e "$pattern" 2>/dev/null
                    fi;;

        "ISO-8859") < "$x" dd conv=ascii 2>/dev/null | grep -q -e "$pattern" 2>/dev/null
                    if [ $? -ne 0 ]
                     then 
                      < "$x" grep -q -e "$pattern" 2>/dev/null
                    fi;;

            "data") < "$x" dd conv=ascii 2>/dev/null | grep -q -e "$pattern" 2>/dev/null
                    if [ $? -ne 0 ]
                     then 
                      < "$x" grep -q -e "$pattern" 2>/dev/null
                    fi;;

           "ASCII") < "$x" grep -q -e "$pattern" 2>/dev/null
                    if [ $? -ne 0 ]
                     then 
                      < "$x" grep -q -e "$pattern" 2>/dev/null
                    fi;;

                 *) < "$x" grep -q -e "$pattern" 2>/dev/null;;
        esac
    then
        total=$((total+1))
        if [ $listado = 1 ]
         then
            echo "$x"
         else
            cp "$x" "$dest" 
        fi
    fi
done

if [ $listado != 1 ] ; then
    echo "$total" files copied to the destiny path "$dest" who contain pattern "$pattern" 
    ls -l "$dest"
fi
exit 1

chrism01 · 04-06-2017, 04:05 AM

Re

Code:

if [ $listado != 1 ] ; then

http://tldp.org/LDP/abs/html/comparison-ops.html; use '-ne'.

I also recommend [[ ]] http://tldp.org/LDP/abs/html/testcon...ml#DBLBRACKETS

kerontide · 04-06-2017, 05:04 AM

Quote:

Originally Posted by chrism01

Re

Code:

if [ $listado != 1 ] ; then

http://tldp.org/LDP/abs/html/comparison-ops.html; use '-ne'.

I also recommend [[ ]] http://tldp.org/LDP/abs/html/testcon...ml#DBLBRACKETS

thanks a lot!!