LinuxQuestions.org - CASE statement

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oracledb0101

06-13-2012 02:17 PM

CASE statement

Code:

case $GROUP_NAME in

        "HR" )

                echo "Primary"  >> $log

        ;;

        "ERP")

                if  $DEPT="ACCOUNTING";  then

                        echo "Secondary" >> $log

              else

              echo "The EXCEPTION DOES NOT WORK" >> $log

                fi

                ;;

        *)

esac

Above is my CASE statement and the exception doesn't see to work if $DEPT is something else rather than "ACCOUNTING", it seems it's on process the "IF" statement even $DEPT is not even in "ACCOUNTING"

Thanks

Ser Olmy

06-13-2012 02:58 PM

The syntax of your if expression is wrong. Try:

Code:

if [ "$DEPT" == "ACCOUNTING" ]; then

oracledb0101

06-13-2012 03:13 PM

thanks

Ser Olmy

06-13-2012 03:15 PM

Huh? If DEPT is not a variable, then what is it?

It doesn't make much sense to compare the text string "DEPT" to the text string "ACCOUNTING".

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