Can sum1 explain how this script works in linux.......
 

for i in `ls -1r`;do sh $i; done;

for i in `ls -1r`; do
sh $i;
done;

It runs all shell scripts in the current directory. It translates out to this:

for every file 'i' in the current directory
call "sh i" (where i is the name of the file)

so, if you had a directory that had the following files:
bar.sh
e.sh
foo.sh
x.sh

it would execute
The -1r argument simply tells ls to list the files in reverse order, one per line.