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Old 02-09-2017, 04:58 AM   #1
mohdwaseemcool007
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Registered: Feb 2017
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Can Some one explain me the output of this (sa -k | head -n 10) command?


Hi,
i am new to linux.I ran this command and printed only top 10 lines. But i cannot understand the last column. can someone please explain this.

sa -K | head -n 10
3302583 420726773.22re 114253.03cp161197553197k*sec
219360 35316397.39re 2472.66cp3904274035k*sec sed
180970 278120.87re 934.95cp1414300569k*sec cut
186 4487426.29re 5050.32cp117563736802k*sec syncsort
71477 11150289.36re 192.27cp291085183k*sec wc
164900 90.40re 69.91cp121205064k*sec ps
42 7293330.18re 74327.23cp275488154064k*sec spmx
1036 43131687.07re 2275.67cp10923058771k*sec dataGrepper
108289 8509.65re 45.98cp 73077242k*sec awk
2418 127686171.11re 19112.76cp1252196688k*sec gzip


thanks

Last edited by mohdwaseemcool007; 02-09-2017 at 05:01 AM.
 
Old 02-09-2017, 05:14 AM   #2
Turbocapitalist
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Welcome to the forum. All programs come with a reference manual, though the quality varies a lot from program to program. So the first place to check is in the reference manual.

Code:
man sa
man head
man man
That will explain the default output and any options for modifying the output. It looks like the last column may be some program name.

Also, it helps with readability to wrap output in [code][/code] tags in your posts.

Which distro are you using, including version? And which package did "sa" come from?
 
  


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